0.6x^2-5.4=0

Solution for 0.6x^2-5.4=0 equation:

0.6x^2-5.4=0

a = 0.6; b = 0; c = -5.4;
Δ = b2-4ac
Δ = 02-4·0.6·(-5.4)
Δ = 12.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.96}}{2*0.6}=\frac{0-\sqrt{12.96}}{1.2}
=-\frac{\sqrt{}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.96}}{2*0.6}=\frac{0+\sqrt{12.96}}{1.2}
=\frac{\sqrt{}}{1.2}
$